Find x and y, if:
Comparing the corresponding elements, we get,
6x - 10 = 8
6x = 18
x = 3
-2x + 14 = 4y
4y = -6+ 14 = 8
y = 2
Find x and y, if:
Comparing the corresponding elements, we get,
3x + 18 = 15
3x = -3
x = -1
12x + 77 = 10y
10y = -12 + 77 = 65
y = 6.5
If ; find x and y, if:
(i) x, y Î W (whole numbers)
(ii) x, y Î Z (integers)
(i) x, y Î W (whole numbers)
It can be observed that the above two equations are satisfied when x = 3 and y = 4.
(ii) x, y Î Z (integers)
It can be observed that the above two equations are satisfied when x = 3 and y = 4.
(i)
(ii)
Evaluate:
If and 3A x M = 2B; find matrix M.
Let the order of matrix M be a x b.
3A x M = 2B
Clearly, the order of matrix M is 2 x 1.
Comparing the corresponding elements, we get,
-3y = -10
y =
12x - 9y = 12
If , find the values of a, b and c.
Comparing the corresponding elements, we get,
a + 1 = 5 a = 4
2 + b = 0 b = -2
-1 - c = 3 c = -4
If A = ; find:
(i) A (BA)
(ii) (AB). B
(i)
(ii)
Find x and y, if:
Comparing the corresponding elements, we get,
5x = 5x = 1
6y = 12 y = 2
If matrix X = and 2X - 3Y =; find the matrix 'X' and 'Y'.
Given ; find the matrix X such that:
A + X = 2B + C
Given, A + X = 2B + C
Find the value of x, given that A2 = B,
Given, A2 = B
Comparing the corresponding elements, we get,
x = 36
If , and I is identity matrix of the same order and At is the transpose of matrix A, find At .B + BI
Let. Find A2 - A + BC.
Let A =. Find A2 + AB + B2.
A =
A2 = A A =
=
AB = A B =
=
=
B2 = B x B =
=
=
A2 + AB + B2 =
=
If and 3A - 2C = 6B, find the values of a, b and c.
Comparing the corresponding elements, we get,
3a - 8 = 24 3a = 32 a =
24 - 2b = 0 2b = 24 b = 12
11 = 6c c =
Given A =.
Find the values of p and q.
A =
BA =
C2 =
BA = C2 =
By comparing,
-2q = -8 q = 4
And p = 8
Given A = . Find AB + 2C - 4D.
AB =
Evaluate:
=
=
A2 = 9A + MI
⇒ A2 - 9A = mI ….(1)
Now, A2 = AA
Substituting A2 in (1), we have
A2 - 9A = mI
(i) Write the order of matrix X.
(ii) Find the matrix 'X'
(i) Let the order of matrix X = m × n
Order of matrix A = 2 × 2
Order of matrix B = 2 × 1
Now, AX = B
∴ m = 2 and n = 1
Thus, order of matrix X = m × n = 2 × 1
Multiplying (1) by 2, we get
4x + 2y = 8 ….(3)
Subtracting (2) from (3), we get
3x = 3
⇒ x = 1
Substituting the value of x in (1), we get
2(1) + y = 4
⇒ 2 + y = 4
⇒ y = 2
Find the matrix C where C is a 2 by 2 matrix.
Given: A2 - 5B2 = 5C
Given matrix . Find the matrix X if, X = B2 - 4B. Hence, solve for a and b given .
To find: a and b
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