Tuesday 7 July 2020

Chapter 17 - Circles Exercise Ex. 17(A)

Question 1

In the given figure, O is the centre of the circle. respectively. Find angle AOC Show your steps of working.

Solution 1

Question 2

In the given figure, BAD = 65°, ABD = 70°, BDC = 45°

(i) Prove that AC is a diameter of the circle.

(ii) Find ACB.

 

Selina Solutions Icse Class 10 Mathematics Chapter - Circles 

Solution 2

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 3

Given O is the centre of the circle and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOB = 70o.Calculate the value of:

(i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesOCA ; (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesOAC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 3

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 4

In each of the following figures, O is the centre of the circle. Find the values of a, b and c.

Solution 4

Question 5

In each of the following figures, O is the centre of the circle. Find the values of a, b, c and d.

Solution 5

Question 6

In the figure, AB is common chord of the two circles. If AC and AD are diameters; prove that D, B and C are in a straight line. O1 and O2 are the centres of two circles.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 6

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 7

In the figure, given below, find:

 Show steps of your working.

Solution 7

Question 8

In the figure, given below, O is the centre of the circle. If

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 8

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 9

Solution 9

Question 10

In the figure given below, ABCD is a cyclic quadrilateral in which Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBAD= 75o ; Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABD= 58o and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesADC = 77o. Find:

(i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBDC, (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCD, (iii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCA.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 10

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 11

In the figure given below, O is the centre of the circle and triangle ABC is equilateral. Find:

(i) ADB, (ii) AEB.

Solution 11

Question 12

Given Selina Solutions Icse Class 10 Mathematics Chapter - CirclesCAB = 75o and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesCBA = 50o. Find the value of Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDAB + Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABD.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 12

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 13

ABCD is a cyclic quadrilateral in a circle with centre O. IfSelina Solutions Icse Class 10 Mathematics Chapter - CirclesADC = 130o, find Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBAC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 13

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 14

In the figure given alongside, AOB is a diameter of the circle and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOC = 110o, find Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBDC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 14

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 15

In the following figure, O is the centre of the circle;Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOB = 60o and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBDC = 100o, find Selina Solutions Icse Class 10 Mathematics Chapter - CirclesOBC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 15

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 16

In ABCD is a cyclic quadrilateral in whichSelina Solutions Icse Class 10 Mathematics Chapter - CirclesDAC = 27o,Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDBA = 50o and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesADB = 33o. Calculate (i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDBC, (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDCB, (iii)Selina Solutions Icse Class 10 Mathematics Chapter - CirclesCAB.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 16

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 17

In the figure given alongside, AB and CD are straight lines through the centre O of a circle. If Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOC = 80o and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesCDE = 40o . Find the number of degrees in: (i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDCE; (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 17

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 18

In the figure given below, AC is a diameter of a circle, whose centre is O. A circle is described on AO as diameter. AE, a chord of the larger circle, intersects the smaller circle at B. Prove that AB = BE.

Solution 18

Question 19

In the following figure,

(i) if Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBAD = 96o, find Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCD and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBFE.

(ii) Prove that AD is parallel to FE.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 19

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 20

Prove that:

(i) the parallelogram, inscribed in a circle, is a rectangle.

(ii) the rhombus, inscribed in a circle, is a square.

Solution 20

Question 21

In the following figure, AB = AC. Prove that DECB is an isosceles trapezium.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 21

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 22

Two circles intersect at P and Q. Through P diameters PA and PB of the two circles are drawn. Show that the points A, Q and B are collinear.

Solution 22

Question 23

The figure given below, shows a circle with centre O. Given: AOC = a and ABC = b.

(i) Find the relationship between a and b

(ii) Find the measure of angle OAB, if OABC is a parallelogram.

Solution 23

Question 24

Two chords AB and CD intersect at P inside the circle. Prove that the sum of the angles subtended by the arcs AC and BD as the centre O is equal to twice the angle APC

Solution 24

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

 

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 25

In the figure given RS is a diameter of the circle. NM is parallel to RS and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesMRS = 29o

Calculate : (i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesRNM ; (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesNRM.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 25

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 26

In the figure given alongside, AB || CD and O is the centre of the circle. If Selina Solutions Icse Class 10 Mathematics Chapter - CirclesADC = 25o; find the angle AEB. Give reasons in support of your answer.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 26

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 27

Two circles intersect at P and Q. Through P, a straight line APB is drawn to meet the circles in A and B. Through Q, a straight line is drawn to meet the circles at C and D. Prove that AC is parallel to BD.

Solution 27

Question 28

ABCD is a cyclic quadrilateral in which AB and DC on being produced, meet at P such that PA = PD. Prove that AD is parallel to BC.

Solution 28

Question 29

AB is a diameter of the circle APBR as shown in the figure. APQ and RBQ are straight lines. Find:

Solution 29

Question 30

In the given figure, SP is the bisector of angle RPT and PQRS is a cyclic quadrilateral. Prove that: SQ = SR.

Solution 30

Question 31

In the figure, O is the centre of the circle, Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOE = 150o, DAO = 51o. Calculate the sizes of the angles CEB and OCE.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 31

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 32

In the figure, P and Q are the centres of two circles intersecting at B and C. ACD is a straight line. Calculate the numerical value of x.

Solution 32

Question 33

The figure shows two circles which intersect at A and B. The centre of the smaller circle is O and lies on the circumference of the larger circle. Given that Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAPB = ao. Calculate, in terms of ao, the value of:

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Give reasons for your answers clearly.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 33

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 34

In the given figure, O is the centre of the circle and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABC = 55o. Calculate the values of x and y.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 34

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 35

In the given figure, A is the centre of the circle, ABCD is a parallelogram and CDE is a straight line. Prove that Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCD = 2Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABE.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 35

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 36

ABCD is a cyclic quadrilateral in which AB is parallel to DC and AB is a diameter of the circle. Given Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBED = 65o; calculate: (i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDAB , (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBDC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 36

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 37

In the given figure, AB is a diameter of the circle. Chord ED is parallel to AB and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesEAB = 63o; calculate: (i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesEBA , (ii)Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCD.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 37

Selina Solutions Icse Class 10 Mathematics Chapter - Circles



(i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAEB = Selina Solutions Icse Class 10 Mathematics Chapter - Circles

(Angle in a semicircle is a right angle)

Therefore Selina Solutions Icse Class 10 Mathematics Chapter - Circles EBA = Selina Solutions Icse Class 10 Mathematics Chapter - Circles - Selina Solutions Icse Class 10 Mathematics Chapter - CirclesEAB = Selina Solutions Icse Class 10 Mathematics Chapter - Circles - Selina Solutions Icse Class 10 Mathematics Chapter - CirclesSelina Solutions Icse Class 10 Mathematics Chapter - Circles


(ii) AB Selina Solutions Icse Class 10 Mathematics Chapter - Circles ED

Therefore Selina Solutions Icse Class 10 Mathematics Chapter - Circles DEB = EBA = Selina Solutions Icse Class 10 Mathematics Chapter - Circles                        (Alternate angles)

Therefore BCDE is a cyclic quadrilateral

Therefore Selina Solutions Icse Class 10 Mathematics Chapter - Circles DEB  Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCD = Selina Solutions Icse Class 10 Mathematics Chapter - Circles

[Pair of opposite angles in a cyclic quadrilateral are supplementary]

Therefore Selina Solutions Icse Class 10 Mathematics Chapter - Circles BCD = Selina Solutions Icse Class 10 Mathematics Chapter - Circles - Selina Solutions Icse Class 10 Mathematics Chapter - Circles = Selina Solutions Icse Class 10 Mathematics Chapter - Circles


Question 38

In the given figure, AB is a diameter of the circle with centre O. DO is parallel to CB and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDCB = 120o; calculate:

(i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDAB, (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDBA, (iii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDBC, (iv) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesADC.

Also, show that the Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOD is an equilateral triangle.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 38

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 39

In the given figure, I is the incentre of the Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABC. BI when produced meets the circumcirle of Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABC at D. Given Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBAC = 55° and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesACB = 65o ; calculate: (i) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDCA, (ii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDAC, (iii) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesDCI, (iv) Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAIC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 39

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 40

A triangle ABC is inscribed in a circle. The bisectors of angles BAC, ABC and ACB meet the circumcircle of the triangle at points P, Q and R respectively. Prove that:

Solution 40

Question 41

Calculate the angles x, y and z if: Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 41

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 42

In the given figure, AB = AC = CD and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesADC = 38o. Calculate:

(i) Angle ABC

(ii) Angle BEC.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 42

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 43

In the given figure, AC is the diameter of circle, centre O. Chord BD is perpendicular to AC. Write down the angles p, q and r in terms of x.

Solution 43

Question 44

In the given figure, AC is the diameter of circle, centre O. CD and BE are parallel. Angle AOB = 80o and angle ACE = 10o. Calculate:

(i) Angle BEC ; (ii) Angle BCD ; (iii) Angle CED.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 44

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 45

In the given figure, AE is the diameter of circle. Write down the numerical value of . Give reasons for your answer.

Solution 45

Question 46

In the given figure, AOC is a diameter and AC is parallel to ED. If , calculate .

Solution 46

Question 47

Use the given figure to find

.

Solution 47

Question 48

In the given figure, AOB is a diameter and DC is parallel to AB. If Selina Solutions Icse Class 10 Mathematics Chapter - CirclesCAB = xo ; find (in terms of x) the values of:

Selina Solutions Icse Class 10 Mathematics Chapter - Circles.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 48

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 49

In the given figure, AB is the diameter of a circle with centre O. BCD = 130°. Find:

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

(i) DAB  (ii) DBA

Solution 49
  1. ABCD is a cyclic quadrilateral

mDAB = 180° - DCB

= 180° - 130°

= 50°

  1. In ∆ADB,

mDAB + mADB + mDBA = 180°

50° + 90° + mDBA = 180°

mDBA = 40°

Question 50

In the given figure, PQ is the diameter of the circle whose centre is O. GivenSelina Solutions Icse Class 10 Mathematics Chapter - CirclesROS = Selina Solutions Icse Class 10 Mathematics Chapter - Circles; calculate Selina Solutions Icse Class 10 Mathematics Chapter - CirclesRTS.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 50

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 51

In the given figure, PQ is a diameter. Chord SR is parallel to PQ. Given that Selina Solutions Icse Class 10 Mathematics Chapter - CirclesPQR = Selina Solutions Icse Class 10 Mathematics Chapter - Circles; calculate

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 51

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 52

AB is the diameter of the circle with centre O. OD is parallel to BC and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAOD = Selina Solutions Icse Class 10 Mathematics Chapter - Circles; calculate the numerical values of:

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 52

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 53

In the given figure, the centre O of the small circle lies on the circumference of the bigger circle. If Selina Solutions Icse Class 10 Mathematics Chapter - CirclesAPB = Selina Solutions Icse Class 10 Mathematics Chapter - Circles and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBCD = Selina Solutions Icse Class 10 Mathematics Chapter - Circles; find:

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 53

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 54

In the given figure, Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBAD = Selina Solutions Icse Class 10 Mathematics Chapter - Circles , Selina Solutions Icse Class 10 Mathematics Chapter - CirclesABD = Selina Solutions Icse Class 10 Mathematics Chapter - Circles and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBDC = Selina Solutions Icse Class 10 Mathematics Chapter - Circles; find:

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Hence, show that AC is a diameter.

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 54

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 55

In a cyclic quadrilateral ABCD, Selina Solutions Icse Class 10 Mathematics Chapter - CirclesA :Selina Solutions Icse Class 10 Mathematics Chapter - CirclesC = 3 : 1 and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesB : Selina Solutions Icse Class 10 Mathematics Chapter - CirclesD = 1 : 5; find each angle of the quadrilateral.

Solution 55

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 56

The given figure shows a circle with centre O andSelina Solutions Icse Class 10 Mathematics Chapter - CirclesABP =Selina Solutions Icse Class 10 Mathematics Chapter - Circles. Calculate the measure of

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 56

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Question 57

In the given figure, M is the centre of the circle. Chords AB and CD are perpendicular to each other. If Selina Solutions Icse Class 10 Mathematics Chapter - CirclesMAD =x and Selina Solutions Icse Class 10 Mathematics Chapter - CirclesBAC = y,

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Selina Solutions Icse Class 10 Mathematics Chapter - Circles

Solution 57

Selina Solutions Icse Class 10 Mathematics Chapter - Circles


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