Solution 1
(i) Given: (x+5)(x-5)=24
(ii)
Given:
(iii)
Given:
or
(iv)
To find : x
Given quadratic equation is …. (i)
One of the roots of (i) is , so it satisfies (i)
So, the equation (i) becomes
Hence, the other root is.
One root of the quadratic equation is -3, find its other root.
Given quadratic equation is …. (i)
One of the roots of (i) is -3, so it satisfies (i)
Hence, the other root is 2a.
If and ;find the values of x.
So, the given quadratic equation becomes
Hence, the values of x are and.
Find the solution of the equation; if and .
Given quadratic equation is ….. (i)
Also, given and
and
So, the equation (i) becomes
Hence, the solution of given quadratic equation are and.
If m and n are roots of the equation where x ≠ 0 and x ≠ 2; find m × n.
Given quadratic equation is
Since, m and n are roots of the equation, we have
and
Hence, .
Solve, using formula :
Given quadratic equation is
Using quadratic formula,
⇒ x = a + 1 or x = -a - 2 = -(a + 2)
Solve the quadratic equation
(i) When (integers)
(ii) When (rational numbers)
(i) When the equation has no roots
(ii) When the roots of are
or
Find the value of m for which the equation has real and equal roots.
Given quadratic equation is
The quadratic equation has real and equal roots if its discriminant is zero.
or
Find the values of m for which equation has equal roots. Also, find the roots of the given equation.
Given quadratic equation is …. (i)
The quadratic equation has equal roots if its discriminant is zero
When , equation (i) becomes
When , equation (i) becomes
∴ x =
Find the value of k for which equation has real roots.
Given quadratic equation is …. (i)
The quadratic equation has real roots if its discriminant is greater than or equal to zero
Hence, the given quadratic equation has real roots for.
Find, using quadratic formula, the roots of the following quadratic equations, if they exist
(i)
(ii)
(i) Given quadratic equation is
D = b2 - 4ac = = 25 - 24 = 1
Since D > 0, the roots of the given quadratic equation are real and distinct.
Using quadratic formula, we have
or
(ii) Given quadratic equation is
D = b2 - 4ac = = 16 - 20 = - 4
Since D < 0, the roots of the given quadratic equation does not exist.
Solve :
(i) and x > 0.
(ii) and x < 0.
(i) Given quadratic equation is
or
But as x > 0, so x can't be negative.
Hence, x = 6.
(ii) Given quadratic equation is
or
But as x < 0, so x can't be positive.
Hence,
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