Represent the following inequalities on real number lines:
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Solution on number line is:
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Solution on number line is:


Solution on number line is:
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Solution on number line is:
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Solution on number line is:
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Solution on number line is:
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Solution on number line is:
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For each graph given, write an inequation taking x as the variable:

For the following inequations, graph the solution set on the real number line:
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The solution set on the real number line is:
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The solution set on the real number line is:
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Represent the solution of each of the following inequalities on the real number line:
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The solution on number line is as follows:


The solution on number line is as follows:

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The solution on number line is as follows:


The solution on number line is as follows:


The solution on number line is:

The solution on number line is:
x
{real numbers} and -1 < 3 - 2x
7, evaluate x and represent it on a number line.
-1 < 3 - 2x
7
-1 < 3 - 2x and 3 - 2x
7
2x < 4 and -2x
4
x < 2 and x
-2
Solution set = {-2
x < 2, x
R}
Thus, the solution can be represented on a number line as:

List the elements of the solution set of the inequation
-3 < x - 2
9 - 2x; x
N.
-3 < x - 2
9 - 2x
-3 < x - 2 and x - 2
9 - 2x
-1 < x and 3x
11
-1 < x
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Since, x
N
Solution set = {1, 2, 3}
Find the range of values of x which satisfies
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Graph these values of x on the number line.
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-3
x and x < 3
-3
x < 3
The required graph of the solution set is:

Find the values of x, which satisfy the inequation:
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Graph the solution on the number line.

Thus, the solution set is {x ∊ N: -2 ≤ x ≤3.75}
Since x ∊ N, the values of x are 1, 2, 3
The solution on number line is given by

Given x
{real numbers}, find the range of values of x for which -5
2x - 3 < x + 2 and represent it on a number line.
-5
2x - 3 < x + 2
-5
2x - 3 and 2x - 3 < x + 2
-2
2x and x < 5
-1
x and x < 5
Required range is -1
x < 5.
The required graph is:

If 5x - 3
5 + 3x
4x + 2, express it as a
x
b and then state the values of a and b.
5x - 3
5 + 3x
4x + 2
5x - 3
5 + 3x and 5 + 3x
4x + 2
2x
8 and -x
-3
x
4 and x
3
Thus, 3
x
4.
Hence, a = 3 and b = 4.
Solve the following inequation and graph the solution set on the number line:
2x - 3 < x + 2
3x + 5, x
R.
2x - 3 < x + 2
3x + 5
2x - 3 < x + 2 and x + 2
3x + 5
x < 5 and -3
2x
x < 5 and -1.5
x
Solution set = {-1.5
x < 5}
The solution set can be graphed on the number line as:
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Solve and graph the solution set of:
(i) 2x - 9 < 7 and 3x + 9
25, x
R
(ii) 2x - 9
7 and 3x + 9 > 25, x
I
(iii) x + 5
4(x - 1) and 3 - 2x < -7, x
R
(i) 2x - 9 < 7 and 3x + 9
25
2x < 16 and 3x
16
x < 8 and x
5![]()
Solution set = { x
5
, x
R}
The required graph on number line is:

(ii) 2x - 9
7 and 3x + 9 > 25
2x
16 and 3x > 16
x
8 and x > 5![]()
Solution set = {5
< x
8, x
I} = {6, 7, 8}
The required graph on number line is:
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(iii) x + 5
4(x - 1) and 3 - 2x < -7
9
3x and -2x < -10
3
x and x > 5
Solution set = Empty set
Solve and graph the solution set of:
(i) 3x - 2 > 19 or 3 - 2x
-7, x
R
(ii) 5 > p - 1 > 2 or 7
2p - 1
17, p
R
(i) 3x - 2 > 19 or 3 - 2x
-7
3x > 21 or -2x
-10
x > 7 or x
5
Graph of solution set of x > 7 or x
5 = Graph of points which belong to x > 7 or x
5 or both.
Thus, the graph of the solution set is:

(ii) 5 > p - 1 > 2 or 7
2p - 1
17
6 > p > 3 or 8
2p
18
6 > p > 3 or 4
p
9
Graph of solution set of 6 > p > 3 or 4
p
9
= Graph of points which belong to 6 > p > 3 or 4
p
9 or both
= Graph of points which belong to 3 < p
9
Thus, the graph of the solution set is:

The diagram represents two inequations A and B on real number lines:


(i) Write down A and B in set builder notation.
(ii) Represent A
B and A
B' on two different number lines.
(i) A = {x
R: -2
x < 5}
B = {x
R: -4
x < 3}
(ii) A
B = {x
R: -2
x < 5}
It can be represented on number line as:
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B' = {x
R: 3 < x
-4}
A
B' = {x
R: 3
x < 5}
It can be represented on number line as:
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Use real number line to find the range of values of x for which:
(i) x > 3 and 0 < x < 6
(ii) x < 0 and -3
x < 1
(iii) -1 < x
6 and -2
x
3
(i) x > 3 and 0 < x < 6
Both the given inequations are true in the range where their graphs on the real number lines overlap.
The graphs of the given inequations can be drawn as:
x > 3
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0 < x < 6
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From both graphs, it is clear that their common range is
3 < x < 6
(ii) x < 0 and -3
x < 1
Both the given inequations are true in the range where their graphs on the real number lines overlap.
The graphs of the given inequations can be drawn as:
x < 0
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-3
x < 1
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From both graphs, it is clear that their common range is
-3
x < 0
(iii) -1 < x
6 and -2
x
3
Both the given inequations are true in the range where their graphs on the real number lines overlap.
The graphs of the given inequations can be drawn as:
-1 < x
6
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-2
x
3
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From both graphs, it is clear that their common range is
-1 < x
3
Illustrate the set {x: -3
x < 0 or x > 2, x
R} on the real number line.
Graph of solution set of -3
x < 0 or x > 2
= Graph of points which belong to -3
x < 0 or x > 2 or both
Thus, the required graph is:
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Given A = {x: -1 < x
5, x
R} and B = {x: -4
x < 3, x
R}
Represent on different number lines:
(i) A
B
(ii) A'
B
(iii) A - B
(i) A
B = {x: -1 < x < 3, x
R}
It can be represented on a number line as:
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(ii) Numbers which belong to B but do not belong to A' = B - A
A'
B = {x: -4
x
-1, x
R}
It can be represented on a number line as:
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(iii) A - B = {x: 3
x
5, x
R}
It can be represented on a number line as:
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P is the solution set of 7x - 2 > 4x + 1 and Q is the solution set of 9x - 45
5(x - 5); where x
R. Represent:
(i) P
Q
(ii) P - Q
(iii) P
Q'
on different number lines.

and

(i) ![]()
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(ii) P - Q = {x: 1 < x < 5, x
R}
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(iii)
{x: 1 < x < 5, x
R}
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Question 19
Question 20
Find the range of values of x, which satisfy:
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Graph, in each of the following cases, the values of x on the different real number lines:
(i) x
W (ii) x
Z (iii) x
R

(i)If x
W, range of values of x is {0, 1, 2, 3, 4, 5, 6}.
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(ii) If x
Z, range of values of x is {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}.
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(iii)If x
R, range of values of x is
.
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Given: A = {x: -8 < 5x + 2
17, x
I}, B = {x: -2
7 + 3x < 17, x
R}
Where R = {real numbers} and I = {integers}. Represent A and B on two different number lines. Write down the elements of A
B
A = {x: -8 < 5x + 2
17, x
I}
= {x: -10 < 5x
15, x
I}
= {x: -2 < x
3, x
I}
It can be represented on number line as follows:
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B = {x: -2
7 + 3x < 17, x
R}
= {x: -9
3x < 10, x
R}
= {x: -3
x < 3.33, x
R}
It can be represented on number line as follows:

A
B = {-1, 0, 1, 2, 3}
Solve the following inequation and represent the solution set on the number line 2x - 5 ≤ 5x +4 < 11, where x
I
2x - 5 ≤ 5x + 4 and 5x +4 < 11
2x - 9 ≤ 5x and 5x < 11 - 4
-9 ≤ 3x and 5x < 7
x
- 3 and x < ![]()
x
- 3 and x < ![]()
Since x
I, the solution set is ![]()
And the number line representation is
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Given that x
I, solve the inequation and graph the solution on the number line:
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Solution set = {5, 6}
It can be graphed on number line as:
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Given:
A = {x: 11x - 5 > 7x + 3, x
R} and
B = {x: 18x - 9
15 + 12x, x
R}.
Find the range of set A
B and represent it on number line.
A = {x: 11x - 5 > 7x + 3, x
R}
= {x: 4x > 8, x
R}
= {x: x > 2, x
R}
B = {x: 18x - 9
15 + 12x, x
R}
= {x: 6x
24, x
R}
= {x: x
4, x
R}
Range of A
B = {x: x
4, x
R}
It can be represented on number line as:
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Find the set of values of x, satisfying:
7x + 3
3x - 5 and
, where x
N.
7x + 3
3x - 5
4x
-8
x
-2

Since, x
N
Solution set = {1, 2, 3, 4, 5}
Solve:
(i)
, where x is a positive odd integer.
(ii)
, where x is a positive even integer.
(i) ![]()

Since, x is a positive odd integer
Solution set = {1, 3, 5}
(ii) ![]()

Since, x is a positive even integer
Solution set = {2, 4, 6, 8, 10, 12, 14}
Solve the inequation:
, x
W. Graph the solution set on the number line.

Since, x
W
Solution set = {0, 1, 2}
The solution set can be represented on number line as:
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Find three consecutive largest positive integers such that the sum of one-third of first, one-fourth of second and one-fifth of third is atmost 20.
According to the given statement,

Thus, the largest value of the positive integer x is 24.
Hence, the required integers are 24, 25 and 26.
Solve the given inequation and graph the solution on the number line.
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2y - 3 < y + 1
4y + 7, y
R
2y - 3 - y < y + 1 - y
4y + 7 - y
y - 3 < 1
3y + 7
y - 3 < 1 and 1
3y + 7
y < 4 and 3y
- 6
y
- 2
- 2
y < 4
The graph of the given equation can be represented on a number line as:
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Solve the inequation:
3z - 5
z + 3 < 5z - 9, z
R.
Graph the solution set on the number line.
3z - 5
z + 3 < 5z - 9
3z - 5
z + 3 and z + 3 < 5z - 9
2z
8 and 12 < 4z
z
4 and 3 < z
Since, z
R
Solution set = {3 < z
4, Z
R }
It can be represented on a number line as:
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Solve the following inequation and represent the solution set on the number line.
-3 < ![]()
R

The solution set can be represented on a number line as:
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Solve the following inequation and represent the solution set on the number line:
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Consider the given inequation:

⇒ -4 ≤ x < 5; where x ∊ R
The solution set can be represented on a number line as follows:

Solve the following in equation, write the solution set and represent it on the number line:
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Solve the following in equation and write the solution set:
13x - 5 < 15x + 4 < 7x + 12, x ∈ R
Represent the solution on a real number line.


Solve the following inequation, write the solution set and represent it on the number line.
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The solution set is represented on number line as follows:
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Solve the following inequation and represent the solution set on a number line.
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As, ![]()
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