Installment per month(P) = Rs. 600
Number of months(n) = 20
Rate of interest (r) = 10% p.a.
The amount that Manish will get at the time of maturity
=Rs (600 x 20)+ Rs 1,050
=Rs 12,000+ Rs 1,050
= Rs 13,050
Installment per month(P) = Rs 640
Number of months(n) = 4.5 × 12 = 54
Rate of interest(r)= 12% p.a.
The amount that Manish will get at the time of maturity
=Rs (640 x 54)+ Rs 9,504
=Rs 34,560+ Rs 9,504
= Rs 44,064
Each of A and B both opened recurring deposit accounts in a bank. If A deposited 1,200 per month for 3 years and B deposited 1,500 per month for years; find, on maturity, who will get more amount and by how much? The rate of interest paid by the bank is 10% per annum.
For A
Installment per month(P) = Rs 1,200
Number of months(n) = 3 × 12 = 36
Rate of interest(r)= 10% p.a.
The amount that A will get at the time of maturity
=Rs (1,200 x 36)+ Rs 6,660
=Rs 43,200+ Rs 6,660
= Rs 49,860
For B
Installment per month(P) = Rs 1,500
Number of months(n) = 2.5 × 12 = 30
Rate of interest(r)= 10% p.a.
The amount that B will get at the time of maturity
=Rs(1,500 x 30)+ Rs 5,812.50
=Rs 45,000+ Rs 5,812.50
= Rs 50,812.50
Difference between both amounts= Rs 50,812.50 - Rs 49,860
= Rs 952.50
Then B will get more money than A by Rs 952.50
Let Installment per month(P) = Rs y
Number of months(n) = 12
Rate of interest(r)= 11%p.a.
Maturity value= Rs (y x 12) + Rs 0.715 y = Rs 12.715 y
Given maturity value= Rs 12,715
Then Rs 12.715 y = Rs 12,715
Let Installment per month(P) = Rs y
Number of months(n) = 3.5 × 12 = 42
Rate of interest(r) = 12% p.a.
Maturity value= Rs(y x 42) + Rs 9.03y = Rs 51.03y
Given maturity value = Rs 10,206
Then Rs 51.03y = Rs 10206
Maturity value= Rs (140 x 48) + Rs (137.20)r
Given maturity value= Rs 8,092
Then Rs(140 x 48)+Rs (137.20)r = Rs 8,092
137.20r = Rs 8,092 - Rs 6,720
r =
(b)
Installment per month(P) = Rs 300
Number of months(n) = 4 × 12 = 24
Let rate of interest(r)= r %p.a.
Maturity value= Rs (300 x 24)+Rs(75)r
Given maturity value = Rs 7,725
Then Rs(300 x 24) + Rs(75)r = Rs 7,725
75 r = Rs 7,725 - Rs 7,200
r =
Installment per month(P) = Rs 150
Number of months(n) = 8
Rate of interest(r)= 8% p.a.
The amount that Manish will get at the time of maturity
=Rs (150 x 8)+ Rs 36
=Rs 1,200+ Rs 36
= Rs 1,236
Installment per month(P) = Rs 350
Number of months(n) = 12 + 3 = 15
Let rate of interest(r)= r %p.a.
Maturity value= Rs (350 x 15) + Rs (35)r
Given maturity value= Rs 5,565
Then Rs (350 x 15) + Rs (35)r = Rs 5,565
35r = Rs 5,565 - Rs 5,250
r =
Installment per month(P) = Rs 1,200
Number of months(n) = n
Let rate of interest(r)= 8 %p.a.
Maturity value= Rs (1,200 x n) + Rs 4n (n + 1)= Rs (1200n + 4n2 + 4n)
Given maturity value= Rs 12,440
Then 1200n + 4n2 + 4n = 12,440
Then number of months = 10
Number of months(n) = n
Let rate of interest(r)= 12 %p.a.
Maturity value= Rs (300 x n) + Rs 1.5n(n + 1)
= Rs (300n + 1.5n2 + 1.5n)
Given maturity value = Rs 8,100
Then 300n + 1.5n2 + 1.5n = 8,100
Then time = 2 years
(i) the total interest earned by Mr. Gupta
(ii) the rate of interest per annum.
(ii)
Installment per month(P) = Rs 2,500
Number of months(n) = 24
Let rate of interest(r)= r %p.a.
Then 625 r = 7500
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